Question

find the base of a parallelogram whose perimeter is [4x^(2)+10x-50]/[(x-3)(x+5)]. and one side is 5/(x-3​

Answer 1

Answer:

Gɪᴠᴇɴ :-

-Perimeter of parallelogram = [4x²+10x-50]/[(x-3)(x+5)].

-One sides of parallelogram = 5/(x - 3) .

Tᴏ Fɪɴᴅ :-

-Base or Other Side of parallelogram .

Fᴏʀᴍᴜʟᴀ ᴜsᴇᴅ :-

-Perimeter of Parallelogram = 2( Base + Other Adjacent Side) .

Sᴏʟᴜᴛɪᴏɴ :-

Comparing The Perimeter now, we get,

➻ [4x²+10x-50]/[(x-3)(x+5)] = 2[ 5/(x - 3) + Base ]

Taking 2 Common From LHS Numerator,

➻2[(2x² + 5x - 25)/(x -3)(x+5)] = 2[ 5/(x - 3) + Base ]

Cancelling 2 from Both Numerator, and taking LCM in RHS part,

➻ [(2x² + 5x - 25)/(x -3)(x+5)] = [ (5 + Base*(x-3))/(x - 3) ]

Cancel (x - 3) From Both Denominator,

➻ [(2x² + 5x - 25)/(x+5)] = (5 + Base*(x-3))

Cross - Multiply,

➻ (2x² + 5x - 25) = (x + 5)((x-3)*Base + 5)

Splitting The Middle Term of LHS part,

➻(2x² + 10x - 5x - 25) = (x + 5)((x-3)*Base + 5)

➻ 2x(x + 5) - 5(x + 5) = (x + 5)((x-3)*Base + 5)

➻ (x + 5)(2x - 5) = (x + 5)((x-3)*Base + 5)

Cancel (x + 5) From Both sides

➻ (2x - 5) = ((x-3)*Base + 5)

➻ (x-3)*Base = (2x - 5) - 5

➻ Base = [(2x - 10)/(x-3)] (Ans.)

Hence, Base of The Given Parallelogram is [(2x - 10)/(x-3)].

HOPE THIS HELPS YOU

PLZZ MARK AS BRAINLIEST

Answer 2

Answer:

yghhuiininiinniinniibibbiibbubuubbuubbininiiinniinnmonniiibnibiibbibiibbuubbubiibnniininniniubvuy. y yy. y ygcy yuv uubbububuinininiininnininniiniibjbbubububuub uibubub j u u hbhvububububhbhk