Question

find the base of a right angle of area 42cm² and height 6 cm​

Answer 1

Answer:

$base = 14 \: cm.$

Step-by-step explanation:

$area = \frac{1}{2} \times b \times h \\ \\ 42 = \frac{1}{2} \times b \times 6 \\ \\ 84 = 6b \\ \\ b = \frac{84}{6} = 14 \: cm \\ \\ b = 14 \: cm.$

Answer 2

Answer.

• High School Math : How to find the area of a right triangle

Study concepts, example questions & explanations for High School Math

Example Questions

High School Math Help » Geometry » Plane Geometry » Triangles » Right Triangles » How to find the area of a right triangle

Find The Area Of A Right Triangle : Example Question #1

A right triangle has a total perimeter of 12, and the length of its hypotenuse is 5. What is the area of this triangle?

Possible Answers:

6

3

10

15

12

Correct answer:

6

Explanation:

The area of a triangle is denoted by the equation 1/2 b x h.

b stands for the length of the base, and h stands for the height.

Here we are told that the perimeter (total length of all three sides) is 12, and the hypotenuse (the side that is neither the height nor the base) is 5 units long.

So, 12-5 = 7 for the total perimeter of the base and height.

7 does not divide cleanly by two, but it does break down into 3 and 4,

and 1/2 (3x4) yields 6.

Another way to solve this would be if you recall your rules for right triangles, one of the very basic ones is the 3,4,5 triangle, which is exactly what we have here

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Find The Area Of A Right Triangle : Example Question #2

The perimeter of a right triangle is 40 units. If the lengths of the sides are x, 2x−1, and x+9 units, then what is the area of the triangle?

Possible Answers:

60 units2

255 units2

136 units2

215 units2

68 units2

Correct answer:

60 units2

Explanation:

Because the perimeter is equal to the sum of the lengths of the three sides of a triangle, we can add the three expressions for the lengths and set them equal to 40.

Perimeter:

P=x+(2x−1)+(x+9)=40

Simplify the x terms.

4x−1+9=40

Simplify the constants.

4x+8=40

Subtract 8 from both sides.

4x=32

Divide by 4

x=8

One side is 8.

The second side is

2x−1=2(8)−1=15.

The third side is

x+9=8+9=17.

Thus, the sides of the triangle are 8, 15, and 17.

The question asks us for the area of the triangle, which is given by the formula (1/2)bh. We are told it is a right triangle, so we can use one of the legs as the base, and the other leg as the height, since the legs will intersect at right angles. The legs of the right triangle must be the smallest sides (the longest must be the hypotenuse), which in this case are 8 and 15. So, let's assume that 8 is the base and 15 is the height.

The area of a triangle is (1/2)bh. We can substitute 8 and 15 for b and h.

Area=12(8)(15)=4(15)=60.

The answer is 60 units squared

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