Question

find the base of a right angled triangle whose perpendicular=12cm hypotenuse=13cm​

Answer 1

Answer:

Let the perpendicular be BC = 12 cm

Base be AB and hypotenuse be AC

By using Pythagoras Theorem, we get

AB^2 + BC^2 = AC^2

or, AB^2 = AC^2 - BC^2

or, AB^2 = 13^2 - 12^2

or, AB^2 = 169 - 144

or, AB = √25

or, AB = 5 cm

So, the length of the base is 5 cm.

MARK THIS AS BRAINLIEST

Answer 2

Base is 5cm

base^ 2 +pependicular^2= hypotenuse ^2

base ^2 +12^2=13^2

base^2= 169-144

base^2=25

base = 5 cm