Question

Find the base of a triangle having area 20sqcm, if its height is 8 cm.​

Answer 1

Answer:

The base of the triangle will be 5 cm

Step-by-step explanation:

Here the area and the height of the triangle is given to be 20 cm² and 8 cm respectively

We have to find the value of base of the triangle

Now, for a triangle the area is given by half the product of its base and height

area of triangle = (1/2) × base × height

20 = (1/2) × base × 8

20 = 4 × base

base = 20/4

base = 5 cm

Answer 2

Question :-

• Find the Base of Triangle having Area 20 cm² and Height 8 cm .

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Answer :-

• Base of Triangle is 5 cm .

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Explanation :-

• Here, Area of Rectangle is given 20 cm . Height is 8 cm . And, we have to calculate the Base of Triangle .

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➻ Formula Required :-

• $\sf{ Area \: _{Traingle} = \frac{1}{2} \times Base \times Height }$

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➻ By substituting the values :-

$\Longrightarrow \: \: \: \sf{ 20 \: = \: \frac{1}{2} \: \times \: Base \times \: 8}$

$\Longrightarrow \: \: \: \sf{20 \: = \: \frac{1}{1} \: \times \: Base \: \times 4 }$

$\Longrightarrow \: \: \: \sf{Base \: = \: \frac{20}{4} }$

$\Longrightarrow \: \: \: \sf{Base \: = \: 5 \: cm}$

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Hence :-

• Base = 5 cm .

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$\begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \pmb {\sf \red{ \dag \: \: More \: Formulas \: \: \dag}}}} \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Square = Side \times Side} \\ \\ \\ \footnotesize\bigstar \: \sf{Area \: of \: Rectangle = Lenght \times Breadth} \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Triangle = \frac{1}{2} \times Base \times Height } \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Parallelogram = Base \times Height} \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Trapezium = \frac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \sf {Area \: of \: Rhombus = \frac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered}$