Question

Find the base of a triangle of height
12cm and area 144 sqcm.​

Answer 1

GiveN :-

• Height of triangle = 12 cm

• Area of triangle = 144 cm²

To FinD :-

• Base of the triangle

SolutioN :-

$\longrightarrow \boxed{ \bf Area= \frac{1}{2} \times B \times H }\\ \\\longrightarrow \sf144= \frac{1}{2} \times12 \times B \\ \\ \longrightarrow \sf6 B = 144 \\ \\\longrightarrow \sf B = \frac{144}{6} \\ \\\longrightarrow \boxed{ \sf B = 24 \: cm}$

Answer 2

Answer :D

Area of Triangle = $\sf\frac{1}{2 } \times base \times height$

Area = $\sf144 {cm}^{2}$

Height = $\sf12 \: cm$

Here,

$\sf144 {cm}^{2} = \frac{1}{ \cancel2} \times base \times \cancel{ {12cm}}^{6cm} \\ \sf =base = \frac{ \cancel{144}}{ \cancel6} = 24cm$

Base = 24 cm