Question

Find the base of a triangle whose altitude is 20 cm and area is 0.8 m2.

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Answer 1

Answer: YOUR ANSWER IS ATTACHED.

Answer 2

Given:

The altitude of a triangle is 20 cm

The area of the triangle is 0.8 m sq.

To find:

The base of the triangle

• In the question, there is cm in altitude and m in the area of the triangle.

• First, we have to make the unit the same.

So,

Converting the area in cm sq.

1 m = 100 cm

1 m² = 10000 cm²

Now,

0.8 m² = 0.8 × 10000 = 8000 cm²

• The formula used to find the area of the triangle with base and altitude is

$\boxed{\pink{\tt{\frac{1}{2} \times base \times altitude}}}$

So,

$\implies \frac{1}{2} \times base \times 20 = 8000$

⇒ 10 × base = 8000

⇒ Base = 8000 ÷ 10

∴ Base = 800 cm

Hence,

The base of the triangle is 800 cm

Also 800cm = 8 m

$\rule{200}2$

• The formula used to find the area of the triangle, when the three sides of the triangle are given,

$\sqrt{S(S-a)(S-b)(S-c)}$  units sq.

Also called Heron's formula.

Here 'S' is the half of the perimeter.

And 'a', 'b', 'c' are the sides of the triangle.