Question

Find the base of a triangle whose altitude is 48 units and area is 12ab sq units

Answer 1

Answer:

0.5ab

Step-by-step explanation:

Attachment is below

Answer 2

Step-by-step explanation:

Given that, altitude of triangle = 48 units

Area of ∆ = 12 ab sq. units

Now,

$area \: of \: triangle = \frac{1}{2} \times base \times height$

$12ab = \frac{1}{2} \times 48 \times base$

$base = \frac{12ab \times 2}{48}$

$base = \frac{ab}{2}$