Question

Find the base of a triangle whose area is 0.4 do ^2 and altitude is 8 cm

Answer 1

CORRECT QUESTION:

❐ Find the base of a triangle whose area is 0.4 cm^2 and altitude is 8 cm.

GIVEN:

• Area of triangle = 0.4 cm²
• Altitude of triangle = 8 cm

TO FIND:

• What is the base of the triangle ?

SOLUTION:

Let the base of the triangle be 'b' cm

We know that the formula for finding the area of the triangle is:-

$\large{\boxed{\bf{\star \: AREA = \dfrac{1}{2} \times BASE \times HEIGHT \: \star}}}$

• AREA = 0.4 cm²
• HEIGHT = 8 cm

According to question:-

On putting the given values in the formula, we get

$\sf{\longmapsto 0.4 = \dfrac{1}{\cancel{2}} \times b \times \cancel{8}}$

$\sf{\longmapsto 0.4 = b \times 4}$

$\sf{\longmapsto \cancel\dfrac{0.4}{4} = b }$

$\bf{\longmapsto 0.1 \: cm = b }$

• BASE = b = 0.1 cm

❝ Hence, the base of the triangle is 0.1 cm ❞

______________________

Answer 2

Cᴏʀʀᴇᴄᴛ Qᴜᴇsᴛɪᴏɴ :

➥ Find the base of a triangle whose area is 0.4 cm² and altitude is 8 cm

Aɴsᴡᴇʀ :

➥ The base of a traingle = 0.1 cm

Gɪᴠᴇɴ :

➤ Area of traingle = 0.4 cm²

➤ Altitude of traingle = 8 cm

Tᴏ Fɪɴᴅ :

➤ The base of a traingle = ?

Sᴏʟᴜᴛɪᴏɴ :

Area of traingle = $\sf\dfrac{1}{2}$ × Base × height

$\sf{: \implies 0.4 = \left(\dfrac{1}{2} \times b \times 8 \right)cm}$

$\sf{: \implies 0.4 = (b \times 4)~cm}$

$\sf{: \implies b = \left(\dfrac{0.4}{4} \right)cm}$

$:\implies \underline{ \overline{ \boxed{ \purple{ \bf{ \: \:b= 0.1 \: cm \: \: }}}}}$

Hence, the base of a traingle is 0.1 cm.