Question

find the base of a triangle whose area is 0.48 dm and altitude is 8 cm​

Answer 1

Step-by-step explanation:

Given,

The altitude of a triangle(h) = 8 cm = 0.1 × 8 dm = 0.8 dm and

The area of a triangle = 0.48 dm^2

To find, the base of a triangle(b) = ?

We know that,

The area of a triangle =\dfrac{1}{2} bh

⇒ \dfrac{1}{2}\times b \times 0.8=0.48

⇒ b \times 0.4=0.48

⇒ b=\dfrac{.48}{0.4}=1.2dm

⇒ b = 1.2 × 10 cm = 12 cm [ since, 1 dm = 10 cm]

Hence, the base of a triangle(b) = 12 cm or 1.2 dm