find the base of a triangle whose area is 0.48 dm sq. and altitude is 8 cm
Answers
Answered by
19
Answer :
➥ The base of a traingle = 12 cm
Given :
➤ Area of a traingle = 0.48 dm
➤ Altitude of a traingle (h) = 8 cm
To Find :
➤ Base of a traingle (b) = ?
Solution :
◈ Area = 0.48 dm = 0.48 × 100 = 48 cm
Let ,
The base of a traingle be "b"
As we know that
Hence, the base of a traingle is 12 cm.
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Additional Information :
What are triangles ?
➜ A triangle is a three-sided polygon, which has three vertices. The three sides are connected with each other end to end at a point, which forms the angles of the triangle. The sum of all three angles of the triangle is equal to 180 degrees.
How many types of triangles ?
➜ There are basically six types of triangles. They are:
- Scalene Triangles
- Isosceles triangles
- Equilateral triangles
- Acute triangles
- Obtuse triangles
- Right triangles
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Answered by
19
Given :-
- Area of a Δ = 0.48dm²
- Altitude of a Δ = 8cm
To Find :-
- The base of a Δ .
Solution :-
➡ Area of a Δ = 0.48 × 100 = 48cm²
As we know that,
[ Putting values ]
➡ 48 = 1/2 × base × 8
➡ 48 = base × 4
➡ base = 48/4
➡ base = 12cm
Hence,
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