Math, asked by anshulsood9742, 10 months ago

Find the base of a triangle whose area is 0.48 dm² and altitude is 8cm

Answers

Answered by vienchiez
5

Answer:

Altitude,h=8cm=0.8dm

Now, area of triangle=0.48dm²

=(1/2)bh=0.48dm²

=(1/2)×b×0.8dm=0.48dm²

=b=(0.48dm²×2)/0.8dm

=b=1.2dm

Thus, the base of the triangle is 1.2dm

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