Find the base of a triangle whose area is 0.48 dm² and altitude is 8cm
Answers
Answered by
5
Answer:
Altitude,h=8cm=0.8dm
Now, area of triangle=0.48dm²
=(1/2)bh=0.48dm²
=(1/2)×b×0.8dm=0.48dm²
=b=(0.48dm²×2)/0.8dm
=b=1.2dm
Thus, the base of the triangle is 1.2dm
Similar questions