Question

Find the base of a triangle whose area is 0.48dm square and altitude is 8cm

Answer 1

area if triangle=1/2 base×altitude. 0.48dm square=48cm square=1/2 base×8 base=48/4 =12cm or 1.2dm

Answer 2

The base of a triangle is "0.12 cm". Further explanation is given below.

Step-by-step explanation:

The given values are:

The Area of a triangle, A = 0.48 cm²

The altitude, a = 8 cm

As we know,

Area = $\frac{1}{2}*base*altitude$

On putting the values in the above question, we get

⇒  0.48 = $\frac{1}{2}*b*8$

⇒  0.48 = 4b

⇒  $\frac{0.48}{4}$ = b

⇒  b = 0.12 cm

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