find the base of a triangle whose area is 132 cm sq and altitude is 22cm
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Answered by
7
Given:-
Area of triangle = 132 cm²
Altitude = 22 cm
Let b be the base and h be the altitude of triangle.
Area of triangle = 1/2*b*h
132 = 1/2*b*22
b = 132*2/22
b = 12 cm Ans.
Ans.) The base of a triangle is 12 cm.
Area of triangle = 132 cm²
Altitude = 22 cm
Let b be the base and h be the altitude of triangle.
Area of triangle = 1/2*b*h
132 = 1/2*b*22
b = 132*2/22
b = 12 cm Ans.
Ans.) The base of a triangle is 12 cm.
Answered by
2
Area of triangle=132 cm^2
Altitude=22cm
Ar of triangle= 1/2*b*h
132 = 1/2* b*22
b= 12cm
Hence,the base of ther triangle is 12cm
Altitude=22cm
Ar of triangle= 1/2*b*h
132 = 1/2* b*22
b= 12cm
Hence,the base of ther triangle is 12cm
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