find the base of a triangle whose area is 132 cm sq and altitude is 22cm
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Area of a Δ = 1/2 bh
where b= base
h = altitude or height.
1/2 bh = 132 cm ²
1 / 2 × b × 22 = 132 cm ²
11 b = 132 cm ²
b = 132 / 11
b = 12 cm
∴ Base of the Δ = 12 cm
Please mark brainliest
where b= base
h = altitude or height.
1/2 bh = 132 cm ²
1 / 2 × b × 22 = 132 cm ²
11 b = 132 cm ²
b = 132 / 11
b = 12 cm
∴ Base of the Δ = 12 cm
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tasneem,please mark mine as brainliest
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