Question

Find the base of a triangle whose area is 220 cm' and height is 11cm.
In a triangle the height is double the base and the area is 400 cm. Find the length of the
muhose length and breadth are 20 cm
8 cm
San
7.
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8.
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base and height.​

Answer 1

$\bigstar \: \: \: \sf We \: Know, \\ \bf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: Base = \frac{2 \times Area}{Height} \\ \\ \bf \: \: \: \: \: = > \: Base = \frac{2 \times 200}{11} = \frac{400}{11} \\ \\ \bf \: \: \: \: \: = > \: Base = \red{36.36} \: cm$

$\bigstar \: \bf \: \: \: Area = 400 \: {cm}^{2} \\ \sf \: \: \: \: \: \: \: Height = 2 \times Breadth \\ \\ Now, \\ \bf \: \: \: \: \: \: = > \: \: 400 = \frac{1}{ \cancel2} \times Breadth \times ( \cancel2 \times Breadth) \\ \bf \: \: \: \: \: = > \: \:400 = {(Breadth)}^{2} \\ \bf \: \: \: \: \: = > \: \:Breadth = \sqrt{400} \\ \bf\: \: \: \: \: = > \: \: Breadth = 20 \: cm \\ \\ Thus, \\ \sf\: \: \: \: \: \: \: Height = \red{40} \: cm \\ \sf\: \: \: \: \: \: \:Breadth = \red{20} \: cm$