Question

Find the base of a triangle whose height is 15cm and area is 45 cm².​

Answer 1

$\red{\sf \: Area \: \: of \: \: ∆ = \frac{1}{2}bh} \\ \\ \sf Given \: \: that ; \\ \sf Area \: \: of \: \: ∆ \: = 15cm² \: \: h= 45cm \\ \\ \sf - > \frac{45 \times 2}{3} = b \\ \\ \ \boxed{\pink{\tt{30cm = base}}}$

Answer 2

$\sf\red{Answer:-}$

Given,

$area \: of \: triangle = {45}cm^{2}$

$Height \: of \: the \: Triangle = 15$

Let Base be = h

Now ,

Area of triangle =

$\implies\frac{1}{2} × base × altitude$

So,

$\implies\ 45= \frac{1}{2} ×15×h$

$\implies\ h= \frac{45 \times 2}{15}$

$\implies\ h=6 cm$

Therefore Base = 6 cm