Question

Find the base of an isosceles triangle whose area is 12 cm2 and one of the equal sides is 5 cm. ​

Answer 1

Answer:

$\huge\mathtt\orange{ANSWER}$

A=bhb

2

hb=a2﹣b2

4

There are 2 solutions forb

b=22A

a2+a4﹣4A2=2·2·12

52+54﹣4·122=6cm

b=22A

a2﹣a4﹣4A2=2·2·12

52﹣54﹣4·122≈8cm