Question

find the base of an isosceles triangle whose area is 12cm and the length of one of the equal side is 5cm​

Answer 1

Answer:

$Area \: of \: triangle = \frac{1}{2} \times b \times h \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:12 = \frac{1}{2} \times b \times 5 \\ \frac{12 \times 2}{5 } = b \\ \frac{24}{5} = b \\ 4.8cm = b$