find the base of an isosceles triangle whose area is 60 square cm and the length of equal side is 13 cm
Answers
Answered by
2
Answer:
34cm
Step-by-step explanation:
as it is given=13*2=26
60-26=34cm
Answered by
1
Answer:
let base x, altitude p and area A
area=1/2(x*p)=60
p=120/x
now, by applying theorem
(x/2)2 + (120/x)2 = 13
solving this equation ,we get;
x=24 , x=10.
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