Question

find the base of isoscels triangle whose area is 60cm^2 and length of one its equal sides is 13cm​

Answer 1

1/2*b*h=area

By Pythagoras theorem,

√{13^2 + (b/2)^2} = h

1/2*b*√{13^2 + (b/2)^2}=60

√{13^2 + (b/2)^2}=120/b

{13^2 + (b/2)^2} = 14400/b^2

Solve this further and get the answer.

Answer 2

Answer:-

1/2(b''h)=area

Pythagoras Theorem:-

√(13^2 + (b/2)^2)= h

1/2(b)√(13^2 + (b/2)^2)=60

√(13^2 + (b/2)^2)=120/b

(13^2 + (b/2)^2) = 14400/b^2