Question

find the base of parallelogram whose area is 320cm and height 8cm​

Answer 1

Given : Area of the Parallelogram is 320 cm and the Height is 8 cm .

To Find : Find the Base of the Parallelogram

$\\ \qquad{\rule{200pt}{2pt}}$

SolutioN :

$\maltese$ Formula Used :

• ${\underline{\boxed{\pmb{\sf{ Area{\small_{(Parallelogram)}} = Base \times Height }}}}}$

$\maltese$ Calculating the Base :

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { Area = Base \times Height } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { 320 = Base \times 8 } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { \dfrac{320}{8} = Base } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; \; \sf { \cancel\dfrac{320}{8} = Base } \\ \\ \\ \end{gathered}$

$\begin{gathered} \qquad \; \longrightarrow \; {\underline{\boxed{\purple{\pmb{\frak{ Base = 40 \; cm }}}}}} \; {\red{\bigstar}} \\ \\ \\ \end{gathered}$

$\therefore \;$ Base of the Parallelogram is 40 cm .

$\\ \qquad{\rule{200pt}{2pt}}$

Answer 2

Answer:

Given : Area of the Parallelogram is 320 cm and the Height is 8 cm .

\begin{gathered} \\ \\ \end{gathered}

To Find : Find the Base of the Parallelogram

\begin{gathered} \\ \qquad{\rule{200pt}{2pt}} \end{gathered}

SolutioN :

\maltese✠ Formula Used :

{\underline{\boxed{\pmb{\sf{ Area{\small_{(Parallelogram)}} = Base \times Height }}}}}

Area

(Parallelogram)

=Base×Height

Area

(Parallelogram)

=Base×Height

\begin{gathered} \\ \\ \end{gathered}

\maltese✠ Calculating the Base :

\begin{gathered} \begin{gathered} \qquad \; \longrightarrow \; \; \sf { Area = Base \times Height } \\ \\ \\ \end{gathered} \end{gathered}

⟶Area=Base×Height

\begin{gathered} \begin{gathered} \qquad \; \longrightarrow \; \; \sf { 320 = Base \times 8 } \\ \\ \\ \end{gathered} \end{gathered}

⟶320=Base×8

\begin{gathered} \begin{gathered} \qquad \; \longrightarrow \; \; \sf { \dfrac{320}{8} = Base } \\ \\ \\ \end{gathered} \end{gathered}

⟶

8

320

=Base

\begin{gathered} \begin{gathered} \qquad \; \longrightarrow \; \; \sf { \cancel\dfrac{320}{8} = Base } \\ \\ \\ \end{gathered} \end{gathered}

⟶

8

320

=Base

\begin{gathered} \begin{gathered} \qquad \; \longrightarrow \; {\underline{\boxed{\purple{\pmb{\frak{ Base = 40 \; cm }}}}}} \; {\red{\bigstar}} \\ \\ \\ \end{gathered} \end{gathered}

⟶

Base=40cm

Base=40cm

★

\begin{gathered} \\ \\ \end{gathered}

\therefore \;∴ Base of the Parallelogram is 40 cm .

\begin{gathered} \\ \qquad{\rule{200pt}{2pt}} \end{gathered}