Question

Find the base of the triangle whose area=2.4 dm square, height=80 cm

Answer 1

Answer:

6cm

Step-by-step explanation:

Let the base be x.

Area= 2.4dm^2 = 2.4 × 10^2= 240cm^2

Height= 80cm

Area of a triangle = 1/2 × base × height

⇒240 = 1/2 × x × 80= 40x⇒ x=240/40=6 cm

Answer 2

Given:

Area of triangle is 2.4 sq.dm.

Height of triangle is 80 cm  

To Find:

Find the Base of triangle  

Solution:

Area of triangle =$\frac{1}{2} \times Base \times Height$

Height of triangle is 80 cm

1 cm = 0.1 dm  

80 cm = $0.1 \times 80 = 8 dm$

Area of triangle =$\frac{1}{2} \times base \times 8$

The area of triangle is 2.4 sq.dm.

So,$\frac{1}{2} \times base \times 8 = 2.4$

Base = $\frac{2.4 \times 2}{8}$

Base =0.6 dm  

Hence The base of triangle is 0.6 dm