Question

Find the Base of this Right angled triangle By Pythagorus Theorem
please tell the Answer
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Answer 1

Step-by-step explanation:

By Pythagoras theorem,

AC²=AB²+BC²

${12}^{2} = {bc}^{2} + {5}^{2} \\ 144 = {bc}^{2} + 25 \\{bc}^{2} + 25 = 144 \\ {bc}^{2} = 144 - 25 \\ {bc}^{2} = 119 \\ bc = \sqrt{119} \\ bc = 11(approx)$