Math, asked by priyanka8253, 1 month ago

find the base so that logarithm of 3125 is 5/2​

Answers

Answered by Mathematically
0

Answer:

25

Step-by-step explanation:

Considering x as the base

log x (3125) = 5/2

[ log a (b) = c ] implies a^c = b

x^5/2 = 3125

[ Because x^5/2 is equal to 3125 exponential operators can be applied on both the sides of equation ]

(x^5/2)^2/5 = (3125) ^2/5

[ (x^a/b)^b/a = x ]

x = [(3125)^1/5] ^2

x = 5^2

x = 25

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