find the base so that logarithm of 3125 is 5/2
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Answer:
25
Step-by-step explanation:
Considering x as the base
log x (3125) = 5/2
[ log a (b) = c ] implies a^c = b
x^5/2 = 3125
[ Because x^5/2 is equal to 3125 exponential operators can be applied on both the sides of equation ]
(x^5/2)^2/5 = (3125) ^2/5
[ (x^a/b)^b/a = x ]
x = [(3125)^1/5] ^2
x = 5^2
x = 25
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