Question

Find the binding energy of a hydrogen atom in the state n = 2.

Answer 1

Explanation:

As two atoms approach each other, the electron each atoms begins to feel the attraction of both nucli

Answer 2

Binding Energy is -3.4 eV

Explanation:

$n_1 = 2, n_2 = \infty$

$E = \frac {-13.6}{n_{1}^{2}} - \frac {-13.6}{n_{2}^{2}}$

= $13.6 (\frac {1}{n_{1}^{2}} - \frac {1}{n_{2}^{2}})$

= $13.6 (\frac {1}{\infty }-\frac {1}{4})$

= $\frac {-13.6}{4}$

= -3.4 eV