Question

Find the binding energy per nucleon of 19779Au if its atomic mass is 196.96 u.

Answer 1

Answer:

B = (Zmp + Nmn – M)C2 Z = 79 ; N = 118 ; mp = 1.007276u ; M = 196.96 u ; mn = 1.008665u B = [(79 x 1.007276 + 118 x 1.008665)u – Mu]c2 = 198.597274 x 931 – 196.96 x 931 = 1524.302094 so, Binding Energy per nucleon = 1524.3 / 197 = 7.737.