find the bquadratic polynomial sum of whose zeroes is 8 and their prodrct is 12 hence find the zeroes of the polynomial
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x^2-8x+12=0
since
x^2-(sum of the zerose)x+(product of the zeroes)
since
x^2-(sum of the zerose)x+(product of the zeroes)
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Sum of zeroes = 8
Product of zeroes = 12
To from the quadratic polynomial we have a formula that is
x²-(sum of zeroes)x+product of zeroes = 0
x²-(8)x+12 = 0
x²-8x+12 = 0
using spitting middle term method
x²-6x-2x+12 = 0
x(x-6)-2(x-6) = 0
(x-2)(x-6) = 0
x-2=0 or x-6=0
x=2 or x=6
so,The zeroes of the quadratic polynomial is 2 and 6
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Product of zeroes = 12
To from the quadratic polynomial we have a formula that is
x²-(sum of zeroes)x+product of zeroes = 0
x²-(8)x+12 = 0
x²-8x+12 = 0
using spitting middle term method
x²-6x-2x+12 = 0
x(x-6)-2(x-6) = 0
(x-2)(x-6) = 0
x-2=0 or x-6=0
x=2 or x=6
so,The zeroes of the quadratic polynomial is 2 and 6
I HOPE THIS WILL HELP YOU MARK ME BRAINLIEST
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