Question

find the breadth of a rectangle field whose length is 3 times its width and its perimeter is 576 M also find area of this field?

Answer 1

perimeter of a rectangle=2(l+b)
let the breadth be x m
it's length be 3x
perimeter=
576 m=2(3x+x)
576=2(4x)
576=8x
therefore,
x=576/8
x=72..m
now,
breadth=x=72 m
length=3x=3×72=216m
now,
area of field=
=l×b
=216×72
=15,552 m sq.

Answer 2

Solution:
Perimeter of the rectangular field=576m (Given)
Let the breadth of the field=x m
So, the length of the field=3x m
Perimeter=2(l+b)
576=2(3x+x)
576=2*4x
576=8x
So, x=72


So,breadth of the field=x m=72m
length of the field=(3x)m=(3*72)m=216
Area of the field=l*b
=216*72
=15552m^2