Question

find the breadth of a rectangle if its lenght is 56m and its perimeter is 192cm​

Answer 1

Answer:

Let the length of the rectangle =l cm and breadth =b cm.

Area of the rectangle =l×b=192cm

2

....(1)

Perimeter of the rectangle =2(l+b)=56 cm

⇒l+b=28 or l=28−b ....(2)

Putting the value of l in equation (1), we get

(28−b)×b=192

28b−b

2

=192

b

2

−28b+192=0

(b−16)(b−12)=0

=>b=16 or 12 cm

Substituting the value of b =16 cm in equation (1), we get

l×16=192

⇒l=12 cm

Similarly, if b =12 cm, l=16 cm.

Dimension of the rectangle are 12 cm and 16 cm.

Answer 2

Step-by-step explanation:

perimeter of rectangle=2(l+b)

196cm=2(56+b)

196/2=56+b

b=98-56

b=42