Math, asked by simrakul123, 3 months ago

Find the breadth of a rectangle of area 24 s q.cm and length 8 cm.

Answers

Answered by Anonymous
2

Answer:

3 cm is the answer

Step-by-step explanation:

hope it helps!!

Answered by BrainlyRish
5

Given: Area of Rectangle is 24 sq.cm and Length of Rectangle is 8 cm .

Need To Find : Breadth of Rectangle.

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❍ Let's consider the Breadth of Rectangle be x .

⠀⠀Finding Area of Rectangle by using the formula is given by :

\underline {\frak{ As,\:We\:Know\:that\::}}\\

⠀⠀⠀⠀⠀\sf{\implies {\underline {Area_{(Rectangle)} = l \times b }}}\\

⠀⠀⠀⠀⠀Here l is the Length of Rectangle in centimeters and b is the Breadth of Rectangle in centimeters and as we have given with Area of Square is 24 cm² .

⠀⠀⠀⠀⠀⠀\underline {\frak{\star\:Now \: By \: Substituting \: the \: Given \: Values \::}}\\

⠀⠀⠀\longmapsto { \tt{ 24 cm^{2} = 8 \times x }}\\

⠀⠀⠀⠀\longmapsto { \tt{ \dfrac{\cancel {24}}{\cancel {8}}  =  x }}\\

⠀⠀⠀⠀⠀\underline {\boxed{\pink{ \mathrm {  x = 3\: cm}}}}\:\bf{\bigstar}\\

Therefore,

  • Breadth of Rectangle is x = 3 cm .

⠀⠀⠀⠀⠀\underline {\therefore\:{ \mathrm { Hence,\: Breadth \:of\:Rectangle \:is\:3\: cm}}}\\

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

\qquad\quad\boxed{\bf{\mid{\overline{\underline{\bigstar\: Verification :}}}}\mid}\\\\\\

\underline {\frak{ As,\:We\:Know\:that\::}}\\

⠀⠀⠀⠀⠀\sf{\implies {\underline {Area_{(Rectangle)} = l \times b }}}\\

⠀⠀⠀⠀⠀Here l is the Length of Rectangle in centimeters and b is the Breadth of Rectangle in centimeters and as we have given with Area of Square is 24 cm² .

⠀⠀⠀⠀⠀⠀\underline {\frak{\star\:Now \: By \: Substituting \: the \: Given \:and\:found\: Values \::}}\\

⠀⠀⠀\longmapsto { \tt{ 24 cm^{2} = 8 \times 3 }}\\

⠀⠀⠀⠀⠀\underline {\boxed{\pink{ \mathrm {  24cm^{2} = 24\: cm^{2}}}}}\:\bf{\bigstar}\\

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀\bf{\sf{\therefore {\underline { Hence \: Verified \:}}}}\\

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

\qquad\quad\boxed{\bf{\mid{\overline{\underline{\large{\bigstar\: More \: to \; know\: :}}}}}\mid}\\\\\\

  • \longrightarrow  {\sf{ Perimeter _{( Triangle)} = Side\:A+Side\:B+Side \:C \:units .}}\\

  • \longrightarrow  {\sf{ Perimeter _{( Rectangle)} = 2( Length + Breadth)\:units .}}\\

  • \longrightarrow  {\sf{ Perimeter _{( Square)} = 4 \times Side \:units .}}\\

  • \longrightarrow  {\sf{ Circumference _{( Circle)} = 2 \times\pi \times Radius \:units .}}\\

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