Question

Find the breadth of a rectangle whose length is 8.2cm and perimeter is 21.2cm

Answer 1

$\huge\mathbb{SOLUTION:-}$

$\sf\bullet Length\:of\: rectangle 8.2\\ \\ \sf\bullet Perimeter=21.2cm$

We have to find the breadth of rectangle

$\underline{\bigstar{\sf{Perimeter=2(Length+Breadth)}}}$

Now

$\bf\underline{\dag{\red{According\:To\: Question}}}$

let the Breadth be n

$\sf\implies 21.2=2(8.2+n)\\ \\ \sf\implies \cancel{\dfrac{21.2}{2}}=8.2+n\\ \\ \sf\implies 10.6=8.2+n\\ \\ \sf\implies 10.6-8.2=n\\ \\ \sf\implies 2.4=n$

The value of n is 2.4 cm which is the breadth of rectangle

$\boxed{\sf{\dag{ \:\: Breadth=2.4cm}}}$

Answer 2

Solution

• Breadth of the rectangle is 2.4 cm

Given

• Length Of The Rectangle = 8.2 cm

• Perimeter Of The Rectangle = 21.2 cm

To finD

• Breadth Of the Rectangle

We Know That,

$\boxed{\boxed{\sf Perimeter \ Of \ Rectangle = 2(l + b) }}$

Putting the values,

$\implies \: \sf \: 21.2 = 2(8.2 + b) \\ \\ \implies \: \sf \: 10.6 = 8.2 + b \\ \\ \implies \: \sf \: b = 10.6 - 8.2 \\ \\ \implies \: \boxed{ \boxed { \sf \: b = 2.4 \: cm}}$