find the breadth of a rectangle whose length is 9cm and diagonal is 41cm. also Find its area...
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Answer:
40cm, 360cm^2
Step-by-step explanation:
Lenght: 9cm = a
Diagonal: 41cm = c
From The Pythogoras Theorm:
a^2 + b^2 = c^2
(9)^2 + b^2 = (41)^2
Therefore,
b^2 = (41)^2 - (9)^2
b = 40,
Therfore, The Breadth = 40cm,
Now,
Area = Length x Breadth
(9) x (40) = (360)cm^2
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