Question

Find the breadth of a rectangular plot of land, if its area is 440 m² and the length is 22m. Also find its perimeter.​

Answer 1

$\huge\underline\mathbb{SOLUTION:-}$

AnsWer:

• The perimeter of a rectangular Park is 84 m.

Given:

• Area of rectangular plot of land = 440 cm².
• Length of rectangular plot of land = 22m

Need To Find:

• Breadth of rectangular plot of land = ?
• Perimeter of rectangular plot of land = ?

Explanation:

Area of rectangular Park = 440 m²

➠ Length × breadth = 440 m²

➠ 22 × breadth = 440

➠ Breadth = $\mathsf {Side = \frac{440}{22} = 20\:m}$

Now, perimeter of rectangular Park = 2(length + breadth)

➠ 2(22 + 20)

➠ 2 × 42

➠ 84 m

• Thus, the perimeter of a rectangular Park is 84 m.

$\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}$

Answer 2

$\color{blue}\huge\underline\mathfrak{Answer}$

$\huge \implies \sf \small \: area \: of \: the \: rectangular \: plot = 440 {m}^{2} \\ \huge \implies \sf \small \: length \: of \: the \: rectangular \: plot \: = 22m \\ \huge\implies \sf \small \: to \: find : \large \: breadth \: \\ \huge \: \implies\huge \sf \small \: let \: the \: breadth \: be \: x \\ \huge \implies \sf \small \: area \: of \: rectangle \: = length \times breadth \\ \huge \implies \: \sf \small \: 440 {m}^{2} = 22m \: \times breadth \: \\ \huge \implies \sf \small \: 440 {m}^{2} = \: 22m \: \times x \: \\ \huge \implies \: \sf \small \frac{440 {m}^{2} }{22m} = \: x \\ \huge \: \implies \sf \small \: x \: = 20m$

$\implies\boxed{\boxed{\underline{\red{\bold{ Breadth\:= 20m }}}}}$

$\bold{Now,}$

$\huge \implies \sf \small \: \: perimeter \: of \: rectangle \: = 2(length + breadth) \\ \huge \implies \sf \small \: 2 \times (22m \: + \: 20m) \\ \huge \implies \tt \small \: 2 \times 42m \\ \huge \implies \sf \large\: 84m$

$\small{\tt{\boxed{\boxed{Perimeter\: of\: rectangular\: plot= \:84m}}}}$