Math, asked by SannidhyaGanguly, 6 months ago

Find the breadth of a rectangular whose broadth
is twice of its length and the perimeter of
rectangle
a
the rectangle is
243​

Answers

Answered by aaravjain1312008
1

Answer:

for rectangle

L -> x

B -> 2x

P -> 243

2(l+b) = P

2 * 3x = 243

2 * x = 243/3

2 * x = 81

x = 81/2

x = 40.5

length = 40.5

breadth = 81

check

P = 2( 81 + 40.5)

P = 2 * 121.5

P = 243

so our answer is correct

Step-by-step explanation:

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