Question

find the breadth of rectangle whose perimeter is 160 cm and whose lenght is
56.5

Answer 1

Answer:

Given:-

Perimeter = 160cm , Length = 56.5cm

Let breadth be b, Then:-

Perimeter of the rectangle = 2(l+b)

∆ 160 => 2(56.5 + b)

80 => 56.5b

b => (80 - 56.5)

=> 23.5cm

Ans:- Breadth = 23.5cm

$\huge\mathbb\purple{Hope~this~helps~u...!!!}$

Answer 2

$\Large\underline\bold{Question:-}$

• Find the breadth of rectangle whose perimeter is 160 cm and whose length is 56.5 cm

$\Large\underbrace\bold{To\:Find:-}$

• Breadth of rectangle

$\Large\underline\bold{Given:-}$

• Perimeter of rectangle = 160 cm
• Length = 56.5 cm

$\Large\underbrace\bold{Solution:-}$

$\bold{Perimeter \: of \: rectangle = 2(l + b)}$

$\implies {160 = 2(56.5 + b)}$

$\implies{160 = 113 + b}$

$\implies160 - 113 = b$

$\implies 47 = b$

Therefore,the breadth of the rectangle is 47 cm.

Formula used here:

• Perimeter of rectangle = 2(l + b)

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