Question

find the breadth of rectangle whose perimeter is 300cm and whose length is 120 CM​

Answer 1

$answer$

perimeter = 300 cm

length = 120 cm

breadth = x

area of a rectangle =

$2(l + b)$

2(120+x)=300 cm

240+2x= 300 cm

2x= 300-240

2x=60

x=

$\frac{60}{2} = 30$

breadth = 30 cm

Answer 2

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GIVEN

• The perimeter of rectangle = 300 cm

• Length of r rectangle = 120 cm

FORMULA

• perimeter of rectangle = 2(l + b)

where • l = Length of rectangle

• b = breadth of rectangle

SOLUTION

• The perimeter of rectangle= 300 cm

$2(120 + b) = 300 \\ \implies \: 120 + b = \frac{\cancel3\cancel0\cancel0}{\cancel2} \\ \implies \: 120 + b = 150 \\ \implies \: b = 150 - 120 = 30$

So breadth of rectangle = 30 cm