find the breadth of regular of plot land whose area is 660 and whose length is 33 M find its.perimeter
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since area of the rectangular plot is 660 m square ...
and hence the length of side is given 33 m
so the breadth is 660/33 = 20 m
perimeter of the rectangular plot is
=2(l+b)
=2(33+20)
=2×53
=106 m
hope this will help you.
thank you.
and hence the length of side is given 33 m
so the breadth is 660/33 = 20 m
perimeter of the rectangular plot is
=2(l+b)
=2(33+20)
=2×53
=106 m
hope this will help you.
thank you.
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