Question

Find the breadth of the rectangle in which :
(d) P = 172 cm, L = 47 cm​

Answer 1

Answer:

39cm

given,

perimeter of the rectangle = 172cm

length of the rectangle = 47cm

to find,

breadth of the rectangle.

$\sf\underline{solution:-}$

perimeter of the rectangle = 2(length+breadth)

let,

the perimeter of the rectangle be :- 'P'

the length of the rectangle be :- 'l'

the breadth of the rectangle be :- 'b'

.: P = 2(l+b)

172cm = 2(47cm+b)

172cm = 2(47cm)+2(b)

172cm = 94cm+2b

2b = 172cm-94cm

2b = 78cm

b = $\sf\dfrac{78cm}{2}$

b = 39cm

.: breadth of the rectangle = 39cm.

formula used :-

$perimeter \: of \: the \: rectangle \: = 2(l + b)$

∆ KNOW MORE. ∆

1) perimeter of square = 4×side

2) perimeter of triangle = sum of its sides.

3) perimeter of rhombus = 4×side

4) perimeter(circumference) of circle = 2πr

5) perimeter of parallelogram = 2(side+base)

6) perimeter of trapezium = sum of its 4 sides

Answer 2

Given that:

Perimeter of rectangle =172 cm

it's Length = 47 cm

To Find :

Breadth of the triangle

Solution:

Perimeter of a rectangle = 2(l+b)

The perimeter of rectangle be : P

The Length of rectangle be : l

The Breadth of a rectangle be : b

Now apply formula 2(l+b)

P=2(l+b)

172=2(47+b)

172= 2(47) + 2(b)

172= 94+2b

2b= 172-94

2b = 78

b= 78/2

b= 39

Answer : breadth of a rectangle = 39

Formula used :

$perimeter \: of \: a \:rectangle \: is \: 2(l + b)$