find the breadth of the rectangle whose length is 52 M 60 cm and perimeter is 140 m
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Perimeter is the distance covered along the boundary of a closed figure.
Perimeter = Sum of the distances or lengths of all the sides
= PQ + QR + RS + SP.
= 3 cm + 2 cm + 1 cm + 4 cm.
= (3 + 2 + 1 + 4) cm
= 10 cm
The perimeter of the given figure is 10 cm.
abhishek588:
wrong
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Heya☺
Perimeter of rectangle = 2(l+b)
140 = 2(52 ×60/100 +b)
70 = 312/10 + b
b = 70 - 312/10
b =( 700-312) ÷10
b= 388÷10
b= 38.8 m
Perimeter of rectangle = 2(l+b)
140 = 2(52 ×60/100 +b)
70 = 312/10 + b
b = 70 - 312/10
b =( 700-312) ÷10
b= 388÷10
b= 38.8 m
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