Find the breadth of the rectangle whose length is 60cm and diagonal is 61cm
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Let the breadth of the rectangle = B
The length of the rectangle = 60 cm
The diagonal of the rectangle= 61cm
by Pythagoras theorem :
(B)^2+(A)^2=(H)^2
(60)^2+(B)^2=(61)^2
3600+(B)^2= 3721
(B)^2=3721-3600
(B)^2=121
B=✓121
B=11.
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