find the breadth of the rectangle whose length is three times its width and it's width and it's perimeter is 568 meters. also find its area of rectangle.
Answers
Answered by
0
Answer:
area= 15123
steps:
2(3b +b)= 568 ⇒b=71
area= 213x71 =15123 sq units
Step-by-step explanation:
Answered by
2
Perimeter of rectangle = 2 (l+b)
= 2 (3b+b)
=2 (4b)
=8b......... (1)
as given p of rectangle= 568m........ (2)
from (1) & (2),
8b=568
b= 568/8
b= 71m
Now
2 (l+b) = 568
2 (l+71)= 568
l+71 = 568/2
l+71 = 284
l = 284 - 71
l = 213m
ar( rectangle ) = l × b
= 213 × 71
= 2 (3b+b)
=2 (4b)
=8b......... (1)
as given p of rectangle= 568m........ (2)
from (1) & (2),
8b=568
b= 568/8
b= 71m
Now
2 (l+b) = 568
2 (l+71)= 568
l+71 = 568/2
l+71 = 284
l = 284 - 71
l = 213m
ar( rectangle ) = l × b
= 213 × 71
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