Question

find the breadth of the rectangle whose perimeter are are 28 cm and length is is 10 cm​

Answer 1

$\sf \bf \huge {\boxed {\mathbb {QUESTION}}}$

$\tt Find\: the\: breadth\: of\: the\: rectangle\: whose\: perimeter\\\tt are\: 28\: cm \:and \:length\: is\:10 \:cm$

$\sf \bf \huge {\boxed {\mathbb {ANSWER}}}$

$\sf \bf {\boxed {\mathbb {GIVEN}}}$

• $\sf \bf Perimeter \:of \:the \:rectangle(P) =28\:cm$
• $\sf \bf Length \:of \:the \:rectangle(l) =10\:cm$

$\sf \bf {\boxed {\mathbb {TO\:FIND}}}$

• $\sf \bf Breadth \:of \:the \:rectangle$

$\sf \bf {\boxed {\mathbb {SOLUTION}}}$

${\pink {\underline {\sf Breadth \:of \:the \:rectangle}}}$

${\blue {\boxed {\boxed {\boxed {\green {\sf \bf P=2(l+b)}}}}}}$

• $\sf P= perimeter \:of \:the \:rectangle$
• $\sf l= length \:of \:the \:rectangle$
• $\sf b= breadth \:of \:the \:rectangle$

${\underbrace {\overbrace {\orange {\bf Substitute \:the \:values}}}}$

$\sf \bf \implies 28=2\Big(10+b\Big)$

$\sf \bf \implies 28=20+2b$

$\sf \bf \implies 28-20=2b$

$\sf \bf \implies 8=2b$

$\sf \bf \implies b=\dfrac{8}{2}$

$\sf \bf \implies b=\dfrac{\cancel{8}}{\cancel{2}}$

$\implies {\orange {\boxed {\boxed {\purple {\mathfrak {b=4\:cm}}}}}}$

${\underbrace {\red {\underline {\red {\overline {\red {\sf \therefore The\:breadth \:of \:the \:rectangle \:is \:4\:cm}}}}}}}$

$\sf \bf \huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}$

___________________________________

$\sf \bf \huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}$

$\bf Area\:of \:the \:rectangle = lb$

$\bf Perimeter \:of \:the \:rectangle = 2(l+b)$

Answer 2

b = ( P/2 ) - l = ( 28/2 ) - 10 = 4cm