Question

find the breadth of the rectangle whose perimeter is 160cm and Whose length is 56.5 Cm​

Answer 1

Given :-

• The rectangle whose perimeter is 160cm and Whose length is 56.5 cm

To find :-

• Breadth of rectangle

Solution :-

• Perimeter of rectangle = 160cm

• Length of rectangle = 56.5cm

As we know that

→ Perimeter of rectangle = 2( l + b )

Where " l " is length and " b " is breadth of a rectangle.

According to the given condition

→ Perimeter of rectangle = 160

→ 2(l + b) = 160

→ (l + b) = 160/2

→ 56.5 + b = 80

→ b = 80 - 56.5

→ b = 23.5 cm

Hence,

• Breadth of rectangle is 23.5cm

Verification :-

• Perimeter of rectangle = 160

→ 2(l + b) = 160

→ 2(56.5 + 23.5) = 160

→ 2 × 80 = 160

→ 160 = 160

• Therefore verified

Answer 2

☯️ Given :-

• Length = 56.5 cm.

• Perimeter = 160cm.

☯️ To Find :-

• Breadth of Rectangle.

☯️ Solution :-

We know that,

Perimeter = 2(l + b).

Now, Put their values.

➙ 160 = 2(56.5 + b).

➙ 56.5 + b = 160/2.

➙ 56.5 + b = 80.

➙ b = 80 - 56.5

➙ b = 23.5 cm.

Hence, Breadth of Rectangle = 23.5 cm.