Find the breath of a rectangle whose perimeter is 360 cm and length is 102
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Answered by
4
perimeter of rectangle=2(l+b)
360=2(102+b)
360/2=102+b
180=102+b
180-102=b
b= 78
360=2(102+b)
360/2=102+b
180=102+b
180-102=b
b= 78
Answered by
0
As we know that,
Perimeter of rectangle = 2(l+b)
360 = 2(102+b)
360/2 = 102+b
180 = 102+b
180 - 102 = b
78 cm = b
Perimeter of rectangle = 2(l+b)
360 = 2(102+b)
360/2 = 102+b
180 = 102+b
180 - 102 = b
78 cm = b
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