Math, asked by priyasaahilgarg, 4 months ago

find the breath of rectangular plot if its area is 330 square meters and the length is 11m. also find its perimeter​

Answers

Answered by Anonymous
76

Answer :

›»› The breadth of a rectangular plot is 30 m and the perimeter of a rectangular plot is 82 m.

Given :

  • Area of a rectangular plot = 220 m².
  • Length of a rectangle plot = 11 m.

To Find :

  • Breadth of a rectangular plot = ?
  • Perimeter of a rectangular plot = ?

Solution :

Let us assume that, the breadth of a rectangular plot is x m.

As we know that

→ Area of a rectangle = length * breadth

→ 330 = 11 * x

→ 330 = 11x

→ x = 330/11

x = 30

The breadth of a rectangular plot is 30 m.

Now,

As we know that

→ Perimeter of a rectangle = 2(length + breadth)

→ Perimeter of a rectangle = 2(l + b)

→ Perimeter of a rectangle = 2(11 + 30)

→ Perimeter of a rectangle = (2 * 11) + (2 * 30)

→ Perimeter of a rectangle = 22 + (2 * 30)

→ Perimeter of a rectangle = 22 + 60

Perimeter of a rectangle = 82

The perimeter of a rectangular plot is 82 m.

Hence, the breadth of a rectangular plot is 30 m and the perimeter of a rectangular plot is 82 m.

Answered by Anonymous
52

Answer:

 \huge \bf \: given

  • Area of rectangular plot = 330 m².
  • Length of rectangular plot = 11 m

 \huge \bf \: to \: find

Breadth and perimeter of rectangular plot.

 \huge \bf \: solution

 \sf \: concept

There is a rectangular plot whose length and area are given and we have to find its perimeter. We shall first find its breadth.

 \huge \boxed { \sf \: Breadth =  \frac{Area}{Length} }

 \sf breadth \:  =  \dfrac{330}{11}

 \sf \: breadth \:  = 30 \: m

Hence breadth = 30 m.

Now,

Finding perimeter

 \huge \fbox {P = 2(L+ B)}

 \sf \: perimeter \:  = 2(11 + 30)

 \sf perimeter \:  = 2(41)

 \sf \: perimeter \:  = 82 \: m

Let's verify

 \sf \: area \:  = l \times b

 \sf \: 330 = 11 \times 30

 \sf \: 330 = 330

Hence,

Breadth of rectangular plot = 30 m

Perimeter of rectangular plot = 82 m

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