Question

find the breath of rectangular plot if its area is 330 square meters and the length is 11m. also find its perimeter​

Answer 1

Answer :

›»› The breadth of a rectangular plot is 30 m and the perimeter of a rectangular plot is 82 m.

Given :

• Area of a rectangular plot = 220 m².
• Length of a rectangle plot = 11 m.

To Find :

• Breadth of a rectangular plot = ?
• Perimeter of a rectangular plot = ?

Solution :

Let us assume that, the breadth of a rectangular plot is x m.

As we know that

→ Area of a rectangle = length * breadth

→ 330 = 11 * x

→ 330 = 11x

→ x = 330/11

→ x = 30

The breadth of a rectangular plot is 30 m.

Now,

As we know that

→ Perimeter of a rectangle = 2(length + breadth)

→ Perimeter of a rectangle = 2(l + b)

→ Perimeter of a rectangle = 2(11 + 30)

→ Perimeter of a rectangle = (2 * 11) + (2 * 30)

→ Perimeter of a rectangle = 22 + (2 * 30)

→ Perimeter of a rectangle = 22 + 60

→ Perimeter of a rectangle = 82

The perimeter of a rectangular plot is 82 m.

Hence, the breadth of a rectangular plot is 30 m and the perimeter of a rectangular plot is 82 m.

Answer 2

Answer:

$\huge \bf \: given$

• Area of rectangular plot = 330 m².
• Length of rectangular plot = 11 m

$\huge \bf \: to \: find$

Breadth and perimeter of rectangular plot.

$\huge \bf \: solution$

$\sf \: concept$

There is a rectangular plot whose length and area are given and we have to find its perimeter. We shall first find its breadth.

$\huge \boxed { \sf \: Breadth = \frac{Area}{Length} }$

$\sf breadth \: = \dfrac{330}{11}$

$\sf \: breadth \: = 30 \: m$

Hence breadth = 30 m.

Now,

Finding perimeter

$\huge \fbox {P = 2(L+ B)}$

$\sf \: perimeter \: = 2(11 + 30)$

$\sf perimeter \: = 2(41)$

$\sf \: perimeter \: = 82 \: m$

Let's verify

$\sf \: area \: = l \times b$

$\sf \: 330 = 11 \times 30$

$\sf \: 330 = 330$

Hence,

Breadth of rectangular plot = 30 m

Perimeter of rectangular plot = 82 m