Find the canvas required to make a covered cubicle of edge 8m
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Given;
Length(l) of the cubicle=8 m.
The canvas required= total surface area of cube
=6l²
=6 x 8 x 8 m²
=6 x 64 m²
=384 m²
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3
Length(l) of the cubicle=8 m.
The canvas required= total surface area of cube
=6l²
=6 x 8 x 8 m²
=6 x 64 m²
=384 m²
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