find the canvas required to make a covered cubicle of edge 8m,in a park?
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The canvas required would be equal to the TSA of the cube.
Therefore, TSA of the cube = 6s² = 6(8)² = 6×64 =384 m²
Therefore, TSA of the cube = 6s² = 6(8)² = 6×64 =384 m²
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