Find the canvas to require to make a covered cube of edge 8m in park?
Answers
Answered by
1
The canvas required would be equal to the TSA of the cube.
Therefore,
TSA of the cube
= 6s²
= 6(8)²
= 6×64
= 384 m²
Therefore,
TSA of the cube
= 6s²
= 6(8)²
= 6×64
= 384 m²
Similar questions