Physics, asked by LuCiFeR2706, 11 months ago

find the capacitance in the given circuit when source is attached at AandB point as shown in figure​

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Answered by Explorer23
0

Answer:

capacitance at A and B= 4/13 × 10^-6 C

Explanation:

C1 and C2 r in series

1/C' = 1 + 1/2 = 3/2 × 10^-6C or C' = 2/3 × 10^-6C

C4 and C3 are in series

C''= 2/3×10^-6C

C", C' and C5 in parallel

1/C = 2/3 + 2/3 + 1/4

C = 4/13 × 10^-6C

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