Question

Find the capacity in gallons of a rectangular tank whose base is 3 ft x 2 ft and a height of 4 feet.​

Answer 1

Answer:

The volume of a rectangular tank is equal to the base area of the tank multiplied by its height. Converting all lengths to inches, we have a tank whose base is 40 inches by 32 inches with a height of 68.5 inches.

Since (volume) = (base area) x (height), the tanks volume is (40 in x 32 in ) x (68.5 in) = 87680 in^3.

Since 1 cubic inch = 0.004329 US gallons, 87680 in^3 x [0.004329 gal/in^3] = 379.57 gallons.

Answer 2

Given,

Base of rectangular tank $\[ = 3ft \times 2ft\]$

Height of rectangular tank $\[ = 4ft\]$

Solution,

Calculate the capacity of rectangular tank.

In this problem capacity of tank measured as volume of tank.

Volume of tank,

= area of tank $\[ \times \]$ height of tank

$\[\begin{array}{l} = 3ft \times 2ft \times 4ft\\ = 24f{t^3}\end{array}\]$

Know that $\[1f{t^3} = 7.481gallon\]$

$\[\begin{array}{l} = 24f{t^3}\\ = 24 \times 7.481gallon\\ = 179.544gallon\end{array}\]$

Hence the capacity in gallon of rectangular tank is $\[179.544gallon\]$.